Types of radioactive decay
Alpha
- He nucleus, 2 protons and 2 neutrons, charged +2
- Due to charge and mass, it is easy to stop
- One sheet of paper stops all alpha particles, even the most energetic
- Energy is quantized. A given isotope produce always alpha with the same energy
- Stopped by 1 inch of air
- Danger only when produced within the body, like if you ingested or breath.
- Quite difficult to detect with GM tubes, as they need an alpha-transparent window, like thin mica
Beta-
- Are electrons, charged -1
- Much ligther than alpha, speed is relativistic
- Energy is distribution, since beta- is accompained by antineutrino. Energy is shared between the two.
- Blocked by few mm of aluminum.
- High energy beta interacts with high atomic weight and produce X rays. Better to stop using low atomic weight, like plastic (plexiglas), wood, water, … Bremsstrahlung radiation. Essentially charged particle is deflected by nuclei, lose some energy what is emitted as photon. Energy is similar to soft gamma, but spectrum is continuum.
- Easy to detect with GM tubes
Penetration r is the max depth the beta electrons can reach in material. After that, all electrons are adsorbed.
\[ r = \frac{0.412}{d} E^{1.29} \]
d is density in g/cm3 (2.702 for aluminium)
E is the energy of the β rays in MeV
Gamma
- It is electromagnetic wave, like visible light, UV or X-rays, microwave, radio, but more energetic
- Stopped by high atomic weight and high densities (-> so lead is good), but total mass per area in the radiation path is the most important.
- Pass through anything, adsorbed/shielded by high mass materials
- Detect with GM tubes easily
- Adsorpion follow exponential decay with thickness of material:
\[ N(x) = N_0 \exp(-\mu x) \]
\[ \ln\left(\frac{N(x)}{N_0}\right) = -\mu x \]
Half-Value Layer. Layer necessary to half the amount of incident gamma radiation
- Concrete: 44.5 mm
- Steel: 12.7 mm
- Lead: 4.8 mm
- Tungsten: 3.3 mm
- Uranium: 2.8 mm
Decrease quadratically with distance. Assuming point emission,
\[ I(r) = \frac{I_0}{4\pi r^2} \]
so that
\[ \frac{I(r_1)}{I(r_2)} = \frac{r_2^2}{r_1^2} \]
doubling the distance, the intensity decreases by 4.
Last update: 29 June 2018